1. If the 1st discarded digit is less than 5, we’ve to leave the remaining digits unchanged.
(e.g. Round off 2.534 to 2 decimal place. The answer is 2.53)
2. If the 1st discarded digit is greater than 5, we’ve to add 1 to the last retained digit.
(e.g. Round off 3.268 to 2 decimal place. The answer is 3.27)
3. If the 1st discarded digit is exactly 5 and there are more non-zero discarded digits, we’ve to add 1 to the last retained digit.
(e.g. Round off 3.2653 to 2 decimal place. The answer is 3.27)
4. If the 1st discarded digit is exactly 5 and all other discarded digits are zero, we’ve to add 1 to the last retained digit if it’s odd and we’ve to leave the last retained digit unchanged if it’s even.
(e.g. Rounding off of 3.265 to 2 decimal place is 3.26 and rounding off of 3.275 to 2 decimal place is 3.28)
* The rule 4 is only applicable in Numerical Analysis. Otherwise add 1 if the 1st discarded digit is 5.
* The rule 4 is only applicable in Numerical Analysis. Otherwise add 1 if the 1st discarded digit is 5.
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